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Salmon often jump waterfalls to reach their breeding grounds. Starting downstream, 1.84 m away from a waterfall 0.251 m in height, at what minimum speed must a salmon jumping at an angle of 38.3 ◦ leave the water to continue upstream? The acceleration due to gravity is 9.81 m/s 2 .

Respuesta :

Answer:

4.73 m/s

Explanation:

R=1.84  m

H=0.251 m

∅=38.3°

For Horizontal Motion

aₓ=0      uₓ=ucos∅

x=uₓt+[tex]\frac{1axt^{2} }{2}[/tex]

R=ucos∅*t+0

1.84=ucos(38.3)*t

t=[tex]\frac{2.344}{u}[/tex]

For Vertical Motion

Y=Uy*t+[tex]\frac{1ayt^{2} }{2}[/tex]

By putting value

0.251=usin∅([tex]\frac{2.344}{u}[/tex])-([tex]\frac{1}{2}g *(\frac{2.344}{u} )^{2}[/tex])

0.251=sin(38.3)([tex]\frac{2.344}[/tex])-([tex]\frac{1}{2}g *(\frac{2.344}{u} )^{2}[/tex])

0.251=1.452-[tex]\frac{83.057}{u^{2} }[/tex]

u²=22.41

u=4.73 m/s