Answer:
9090.90 Km/s
Explanation:
Given:
hydrogen has a spectral line at = 165 nm
Line is observed at = 170 nm
Now, from the Hubble's law
[tex]v=\frac{\Delta\lambda}{\lambda}\times\ C[/tex]
Where,
v is the velocity
Δλ = Change in wavelength = 170 - 165 = 5 nm
λ = Actual wavelength
C is the speed of the light
on substituting the respective values, we get
[tex]v=\frac{5}{165}\times3times10^8[/tex]
or
v = 90.90909 × 10⁵ m/s
or
v = 9090.90 Km/s
