Answer:26.96 m,2.34 s
Explanation:
Given
Wrench hit the ground with a speed of 23 m/s
Applying equation of motion
[tex]v^2-u^2=2as[/tex]
Here u=0 because it is dropped from a height of S m
[tex]23^2-0=2\times 9.81\times s[/tex]
[tex]s=\frac{529}{2\times 9.81}=26.96 m[/tex]
Time required by wrench to hit the ground
v=u+at
[tex]23=9.81\times t[/tex]
[tex]t=\frac{23}{9.81}=2.34 s[/tex]
