Answer:
When you prepared the solution, you will find that the molarity is 0.73M
Explanation:
First of all you should get by the periodic table, molar mass in the anhydrouds calcium.
CaCl2 · 0H20 = 110.98 g/m
Now we have to find out how many mols are 15 g.
So 15g / 110.98 g/m = 0.135 moles
This moles are in 185 ml of water. Molarity as you should know are moles of solute in 1 L of solution (either 1000 ml)
185 ml ______ 0.135 moles
1000 ml _____ x x = (1000*0.135) /185 = 0.730M
