Respuesta :
Answer:
[tex]A. 8.29\times 10^{-18}\ J[/tex]
Explanation:
Given that:
p = magnitude of charge on a proton = [tex]1.6\times 10^{-19}\ C[/tex]
k = Boltzmann constant = [tex]9\times 10^{9}\ Nm^2/C^2[/tex]
r = distance between the two carbon nuclei = 1.00 nm = [tex]1.00\times 10^{-9}\ m[/tex]
Since a carbon nucleus contains 6 protons.
So, charge on a carbon nucleus is [tex]q = 6p=6\times 1.6\times 10^{-19}\ C=9.6\times 10^{-19}\ C[/tex]
We know that the electric potential energy between two charges q and Q separated by a distance r is given by:
[tex]U = \dfrac{kQq}{r}[/tex]
So, the potential energy between the two nuclei of carbon is as below:
[tex]U= \dfrac{kqq}{r}\\\Rightarrow U = \dfrac{kq^2}{r}\\\Rightarrow U = \dfrac{9\times10^9\times (9.6\times 10^{-19})^2}{1.0\times 10^{-9}}\\\Rightarrow U =8.29\times 10^{-18}\ J[/tex]
Hence, the energy stored between two nuclei of carbon is [tex]8.29\times 10^{-18}\ J[/tex].
