Answer:
4.56 seconds
63.25 m
Explanation:
t = Time taken for the car to stop
u = Initial velocity = 60 km/h = 100 km/h = 100000/3600 = 27.78 m/s
v = Final velocity = 0
s = Displacement
a = Acceleration = -6.1 m/s²
Time taken by the car to stop
[tex]v=u+at\\\Rightarrow t=\frac{v-u}{a}\\\Rightarrow t=\frac{0-27.78}{-6.1}\\\Rightarrow t=4.56\ s[/tex]
Time taken by the car to stop is 4.56 seconds
[tex]s=ut+\frac{1}{2}at^2\\\Rightarrow s=27.78\times 4.56+\frac{1}{2}\times -6.1\times 4.56^2\\\Rightarrow s=63.25\ m[/tex]
The total stopping distance would be 63.25 m
