A glittering glass globe is given a net electric charge of 5.31 × 10^-6 C. Does the globe now have more or fewer electrons than it does in its neutral state? How many more or fewer?

Respuesta :

Answer:

[tex]N=3.32*10^{13}[/tex] electrons

Explanation:

The electric charge Q+ =5.31 × 10^-6 C, is positive.That is because the glittering glass globe lost electrons (negative charges), and remain a positive net electric charge. The total charge Q+ at the globe is equal, but with opposite sign, to the charge negative Q- removed of it. Q- is the sum of the charge of the N electrons removed from the globe:

[tex]Q_{-}=N*q_{e}[/tex]

[tex]Q_{-}=-Q_{+}[/tex]

q_{e}=-1.6*10^{-19}C    charge of a electron

We solve to find N:

[tex]N=-Q_{+}/q_{e}=-5.31*10^{-6}/(-1.6*10^{-19})=3.32*10^{13}[/tex]