Answer:
The current in the wire under the influence of the force is 216.033 A
Solution:
According to the question:
Length of the wire, l = 0.676 m
[tex]\theta = 57.7^{\circ}[/tex]
Magnetic field of the Earth, [tex]B_{E} = 5.29\times 10^{- 5} T[/tex]
Forces experienced by the wire, [tex]F_{m} = 6.53\times 10^{-3} N[/tex]
Also, we know that the force in a magnetic field is given by:
[tex]F_{m} = IB_{E}lsin\theta[/tex]
[tex]I = \frac{F_{m}}{B_{E}lsin\theta}[/tex]
[tex]I = \frac{6.53\times 10^{-3}}{5.29\times 10^{- 5}\times 0.676sin57.7^{\circ}[/tex]
I = 216.033 A
