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We attach two blocks of masses m1 = 7 kg and m2 = 7 kg to either end of a spring of spring constant k = 1 N/m and set them into oscillation. Calculate the angular frequency ω of the oscillation.

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Answer:

The angular frequency [tex]\omega[/tex] of the oscillation is [tex]0.58s^{-1}[/tex]

Explanation:

For this particular situation, the angular frequency of the system is given by

[tex]\omega=\sqrt{\frac{m_1+m_2}{m_1m_2}k}=\sqrt{\frac{7 kg+5 kg }{7kg *5 kg}1\frac{N}{m}}=\sqrt{\frac{3}{35s^2}}\approx 0.58s^{-1}[/tex]