A block is placed at the top of a frictionless inclined plane with angle 30 degrees and released. The incline has a height of 15 m and the block has mass 2 kg. In the above problem the speed of the block when it reaches the bottom of the incline is 8.3 m/s 17 m/s 25 m/s 30 m/s

Respuesta :

Answer:

The speed of the block when it reaches the bottom is 17 m/s.

(b) is correct option.

Explanation:

Given that,

Height = 15 m

Mass = 2 kg

We need to calculate the speed of the block when it reaches the bottom

Using conservation of energy

[tex]mgh=\dfrac{1}{2}mv^2[/tex]

[tex]v^2=2gh[/tex]

[tex]v=\sqrt{2gh}[/tex]

Where, g = acceleration due to gravity

h = height

Put the value into the formula

[tex]v=\sqrt{2\times9.8\times15}[/tex]

[tex]v=17\ m/s[/tex]

Hence, The speed of the block when it reaches the bottom is 17 m/s.