Respuesta :
Explanation:
Given that,
Charge 1, [tex]q_1=-23\ C[/tex]
Charge 2, [tex]q_1=+67\ C[/tex]
Distance between charges, r = 3.18 cm = 0.0318 m
(a) Let F is the magnitude of force that each sphere experiences. The force is given by :
[tex]F=k\dfrac{q_1q_2}{r^2}[/tex]
[tex]F=9\times 10^9\times \dfrac{-23\times 67}{(0.0318)^2}[/tex]
[tex]F=-1.37\times 10^{16}\ N[/tex]
(b) The spheres are brought into contact and then separated to a distance of 3.18 cm. When they are in contact, both possess equal charges. Net charge is :
[tex]q=\dfrac{q_1+q_2}{2}[/tex]
[tex]q=\dfrac{-23+67}{2}=22\ C[/tex]
Electric force is given by :
[tex]F=9\times 10^9\times \dfrac{22^2}{(0.0318)^2}[/tex]
[tex]F=4.307\times 10^{15}\ N[/tex]
Hence, this is the required solution.
