Answer:
36.13 m/s
Explanation:
initial speed, u = 56 km/h = 15.56 m/s
distance, s = 25 m
t = 2.11 s
Let the speed of the car at the impact is v and the acceleration is a.
Use second equation of motion
[tex]s=ut+\frac{1}{2}at^{2}[/tex]
[tex]25=1.56 \times 2.11+\frac{1}{2}\times a \times 2.11^{2}[/tex]
a = 9.75 m/s^2
Use first equation of motion
v = u + at
v = 15.56 + 9.75 x 2.11
v = 36.13 m/s
