Answer : The number of oxygen atoms present in glucose are [tex]24.10\times 10^{23}[/tex]
Explanation :
First we have to calculate the moles of glucose.
[tex]\text{moles of glucose}=\frac{\text{Mass of glucose}}{\text{Molar mass of glucose}}[/tex]
Molar mass of glucose = 180 g/mole
[tex]\text{moles of glucose}=\frac{120.0g}{180g/mole}=0.667mole[/tex]
Now we have to calculate the number of oxygen atoms.
The formula of glucose is, [tex]C_6H_{12}O_6[/tex].
In the glucose molecule, there 6 atoms of carbon, 12 atoms of hyrogen and 6 atoms of oxygen.
As, 1 mole of glucose contains [tex]6\times 6.022\times 10^{23}[/tex] number of oxygen atoms
So, 0.667 mole of glucose contains [tex]0.667\times 6\times 6.022\times 10^{23}=24.10\times 10^{23}[/tex] number of oxygen atoms
Therefore, the number of oxygen atoms present in glucose are [tex]24.10\times 10^{23}[/tex]
