Answer: [tex]\bold{y=-\dfrac{3}{2}x+\dfrac{15}{2}}[/tex]
Step-by-step explanation:
First, use the slope formula: [tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
Then input the slope (m) and ONE of the points (x₁, y₁) into the
Point-Slope formula: y - y₁ = m(x - x₁)
[tex]m=\dfrac{3-6}{3-1}\quad =\dfrac{-3}{2}\quad \implies \quad m=-\dfrac{3}{2}\\\\\\\\y-3=-\dfrac{3}{2}(x-3)\\\\\\y-3=-\dfrac{3}{2}x+\dfrac{9}{2}\\\\\\y\quad =-\dfrac{3}{2}x+\dfrac{15}{2}[/tex]
