Answer:
For ²⁰⁸Pb²⁺ cation, the sum of the number of neutrons and electrons = 206
Explanation:
Lead, chemical symbol Pb, is a chemical element which belongs to the group 14 of the periodic table. The atomic number of lead is 82 and it is a member of the p-block.
The isotope of lead with the mass number 208, has 126 neutrons.
Since, atomic number = number of protons = number of electrons for neutral atom
Therefore, for ²⁰⁸Pb: number of electrons= 82
So, for ²⁰⁸Pb²⁺ cation: number of electrons= 82 - 2 = 80
Therefore, for ²⁰⁸Pb²⁺ cation, the sum of the number of neutrons and electrons = number of electrons + number of neutrons = 80 electrons + 126 neutrons = 206.
