Answer: The mass of carbon dioxide produced is 27.1 grams.
Explanation:
Combustion reaction is defined as the reaction in which a hydrocarbon reacts with oxygen gas to produce carbon dioxide gas and water molecule.
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] .....(1)
Given mass of butane = 8.9541 g
Molar mass of butane = 58.12 g/mol
Putting values in equation 1, we get:
[tex]\text{Moles of butane}=\frac{8.9541g}{58.12g/mol}=0.154mol[/tex]
The chemical equation for the combustion of butane follows:
[tex]2C_4H_{10}+13O_2\rightarrow 8CO_2+10H_2O[/tex]
By Stoichiometry of the reaction:
2 moles of butane produces 8 moles of carbon dioxide
So, 0.154 moles of butane will produce = [tex]\frac{8}{2}\times 0.154=0.616mol[/tex] of carbon dioxide
Now, calculating the mass of carbon dioxide by using equation 1, we get:
Moles of carbon dioxide = 0.616 moles
Mass of carbon dioxide = 44 g/mol
Putting values in equation 1, we get:
[tex]0.616mol=\frac{\text{Mass of carbon dioxide}}{44g/mol}\\\\\text{Mass of carbon dioxide}=27.1g[/tex]
Hence, the mass of carbon dioxide produced is 27.1 grams.