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An airplane is heading due south at a speed of 430 km/h . A wind begins blowing from the northwest at a speed of 85.0 km/h (average).What should the plane's course shift be so that it will fly due south?

Respuesta :

Answer:

It should fly 8° to west of south at 430km/h

Explanation:

According to the diagram. X components for both velocities must have the same magnitude in order to get the resultant velocity due south.

[tex]V_{w}*cos(45) = V_{A}*sin(\alpha )[/tex]   Solving for α:

α = 8.03°

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