Answer:
6
Explanation:
Number of lines emanate from + 5 micro coulomb is 15 .
They terminates at negative charges that means at - 3 micro coulomb and - 2 micro Coulomb.
the electric field lines terminates at - 3 micro Coulomb and - 2 micro Coulomb is in the ratio of 3 : 2.
So the lines terminating at - 3 micro coulomb
= [tex]\frac{3}{5}\times 15 = 9[/tex]
So the lines terminating at - 2 micro coulomb
= [tex]\frac{2}{5}\times 15 = 6[/tex]
So, the number of filed lines terminates at - 2 micro Coulomb are 6.
The number of lines emanating from the negative charged particles are 9.09 and 6.06 respectively.
In an electric field, the number of lines emanating from a charged particle is directly proportional to the magnitude of the charge. Thus, this is given by this mathematical expression:
[tex]q \;\alpha \;L\\\\q=kL\\\\5=k15\\\\k=\frac{5}{15}[/tex]
k = 0.33.
For the -3.0 μC particle:
[tex]L=\frac{q}{k} \\\\L=\frac{3.0}{0.33}[/tex]
L = 9.09.
For the -2.0 μC particle:
[tex]L=\frac{q}{k} \\\\L=\frac{2.0}{0.33}[/tex]
L = 6.06.
Read more on charges here: brainly.com/question/4313738
