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A 9.0 μF capacitor, a 13 μF capacitor, and a 16 μFcapacitor are connected in series. What is their equivalent capacitance? Express your answer using two significant figures.

Respuesta :

Answer:

Equivalent capacitance, [tex]C'=3.9\ \mu F[/tex]

Explanation:

Capacitance, [tex]C_1=9\ \mu F[/tex]

Capacitance, [tex]C_2=13\ \mu F[/tex]

Capacitance, [tex]C_3=16\ \mu F[/tex]

Let C' is the equivalent capacitance of the combination of capacitors. It is given by :

[tex]\dfrac{1}{C'}=\dfrac{1}{C_1}+\dfrac{1}{C_2}+\dfrac{1}{C_3}[/tex]

[tex]\dfrac{1}{C'}=\dfrac{1}{9}+\dfrac{1}{13}+\dfrac{1}{16}[/tex]

[tex]C'=3.99\ \mu F[/tex]

or

[tex]C'=3.9\ \mu F[/tex]

So, their equivalent capacitance is [tex]3.9\ \mu F[/tex]. Hence, this is the required solution.