Respuesta :
Explanation:
Relation between molarity and molar mass is as follows.
Molarity = [tex]\frac{mass}{\text{molar mass}} \times \frac{1000}{V (in ml)}[/tex]
It is given that mass is 1 mg/ml which is also equal to [tex]10^{-3}[/tex] g.
Molecular mass = 58 Da = 58 g/mol
Volume = 1 ml
Therefore, calculate molarity as follows.
Molarity = [tex]\frac{mass}{\text{molar mass}} \times \frac{1000}{V (in ml)}[/tex]
= [tex]\frac{10^{-3}g}{58 g/mol} \times \frac{1000}{1 ml}[/tex]
= 0.0172 molar
It is known that 1 molar equals 1000 millimolar.
So, 0.0172 molar = [tex]0.0172 molar \times \frac{1000 millimolar}{1 molar}[/tex]
= 17.2 millimolar
Thus, we can conclude that the concentration of given solution is 17.2 millimolar.
