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A positive point charge on a 2-D plane starts at the position (2 cm, 7 cm). It moves along an equipotential line to the position (10 cm, 7 cm). The plane is oriented parallel to a
uniform electric field of 120 N/C. How much work does the electric field do in this scenario? (Answer in Joules, J. You do not need to type the units, only the number.)

Respuesta :

Answer:

W = 0

Explanation:

given data:

starting position is ( 2cm , 7 cm)

ending position is  (10 cm, 7 cm)

we know thta work done is given as

[tex] W = q\Delta v[/tex]

here , q is particle charge

[tex]\Delta v[/tex] is change in potential

as we know that intial and final position are having uniform eleectric potential, therefore it have same potential i.e. V_1 = V_2, thus

one more reason of being work done equal to zero is,

Since the distance covered by the item and the direction of motion is always perpendicular to each other during the round journey, no work is therefore carried out.

W = 0

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