Explanation:
The position of a particle along x - axis is given by :
[tex]x=2.08+3.06t-1t^2[/tex]
(a) Position at t = 3.3 s
[tex]x=2.08+3.06(3.3)-1(3.3)^2[/tex]
x = 1.288 m
(b) Velocity at t = 3.3 s
[tex]v=\dfrac{dx}{dt}[/tex]
[tex]v=\dfrac{d(2.08+3.06t-1t^2)}{dt}[/tex]
[tex]v=3.06-2t[/tex]
at t = 3.3 s
[tex]v=3.06-2(3.3)[/tex]
v = -3.54 m/s
(c) Acceleration,
[tex]a=\dfrac{dv}{dt}[/tex]
[tex]a=\dfrac{d(3.06-2t)}{dt}[/tex]
[tex]a=-2\ m/s^2[/tex]
Hence, this is the required solution.
