Answer:
Option d)
Solution:
As per the question:
Work done by farm hand, [tex]W_{FH} = 972J[/tex]
Force exerted, F' = 310 N
Angle, [tex]\theta = 23^{\circ}[/tex]
Now,
The component of force acting horizontally is F'cos[tex]\theta[/tex]
Also, we know that the work done is the dot or scalar product of force and the displacement in the direction of the force acting on an object.
Thus
[tex]W_{FH} = \vec{F'}.\vec{d}[/tex]
[tex]972 = 310\times dcos23^{\circ}[/tex]
d = 3.406 m = 3.4 m