Respuesta :
Answer:
[tex]-1.144\ \mu C[/tex]
Explanation:
Given:
- [tex]\vec{E}[/tex] = uniform electric field in the space = [tex](148.0\ \hat{i}-110.0\ \hat{j})\ N/C[/tex]
- Q = Charge placed in the region = [tex]10.4 nC\ = 1.04\times 10^{-8}\ nC[/tex]
Assume:
- [tex]\vec{F}[/tex] = Electric force on the charge due to electric field
We know that the electric field is the electric force applied on a unit positive charge i.e.,
[tex]\vec{E}=\dfrac{\vec{F}}{Q}[/tex]
This means the electric force applied on this additional charge placed in the field is given by:
[tex]\vec{F}=Q\vec{E}\\\Rightarrow \vec{F} = 1.04\times 10^{-8}\ n C\times (148.0\ \hat{i}-110.0\ \hat{j})\ N/C\\\Rightarrow \vec{F} = (1.539\ \hat{i}-1.144\ \hat{j})\ \mu N\\[/tex]
From the above expression of force, we have the following y-component of force on this additional charge.
[tex]F_y = -1.144\ \mu N[/tex]
Hence, the y-component of the electric force on the this charge is [tex]-1.144\ \mu N[/tex].
