Answer:
The percent by mass of chromium(II) acetate in the solution is 4.42%.
Explanation:
Molality of the chromium(II) acetate solution = 0.260 m = 0.260 mol/kg
This means that in 1 kg of solution 0.260 moles of chromium(II) acetate are present.
1000 g = 1 kg
So, in 1000 grams of solution 0.260 moles of chromium(II) acetate are present.
Then in 100 grams of solution = [tex]\frac{0.260 mol}{1000}\times 100=0.0260 mol[/tex]
Mass of 0.0260 moles chromium(II) acetate:
= 0.0260 mol × 170 g/mol = 4.42 g
[tex](w/w)\%=\frac{\text{mass of solute in 100 gram solution}}{100}\times 100[/tex]
[tex]=\frac{4.42 g}{100 g}\times 100=4.42\%[/tex]
The percent by mass of chromium(II) acetate in the solution is 4.42%.
