Answer:
9.2584 mol/L is the solubility of helium in water at 25 °C.
Explanation:
Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the liquid.
To calculate the molar solubility, we use the equation given by Henry's law, which is:
[tex]C_{He}=K_H\times p_{H_2O}[/tex]
where,
[tex]K_H[/tex] = Henry's constant = [tex]3.26\times 10 mol/L atm[/tex]
[tex]p_{He}[/tex] = partial pressure of carbonated drink = 0.284 atm
Putting values in above equation, we get :
[tex]C_{He}=3.26\times 10 mol/L atm\times 0.284 atm=9.2584 mol/L[/tex]
9.2584 mol/L is the solubility of helium in water at 25 °C.