Answer:
the expected distance is 4.32 m
Explanation:
given data
half life time = 1.8 × [tex]10^{-8}[/tex] s
speed = 0.8 c = 0.8 × 3 × [tex]10^{8}[/tex]
to find out
expected distance over
solution
we know c is speed of light in air is 3 × [tex]10^{8}[/tex] m/s
we calculate expected distance by given formula that is
expected distance = half life time × speed .........1
put here all these value
expected distance = half life time × speed
expected distance = 1.8 × [tex]10^{-8}[/tex] × 0.8 × 3 × [tex]10^{8}[/tex]
expected distance = 4.32
so the expected distance is 4.32 m
