Answer:
a)
3.43*10^{14} Hz
8.75*10^{-7} m
b)
2.70*10^{14} Hz
1.10*10^{-6} m
Explanation:
GIVEN DATA:
a)
i)we know that
E = h\nu
where E is energy
h = plank's constant = 6.625* 10^{-34} j-s
[tex]\nu = frequency[/tex]
[tex]\nu = \frac{E}{h} = \frac{1.42*1.6*10^{-19} v}{6.625*10^{-34}}[/tex]
[tex]\nu = 3.43*10^{14} Hz[/tex]
ii)wavelength is given as
[tex]\lambda = \frac{c}{\nu}[/tex]
[tex]= \frac{3*10^8}{3.43*10^{14}} = 8.75*10^{-7} m[/tex]
b) i) i)we know that
[tex]E = h\nu[/tex]
where E is energy
h = plank's constant = 6.625* 10^{-34} j-s
[tex]\nu = frequency[/tex]
[tex]\nu = \frac{E}{h} = \frac{1.12*1.6*10^{-19} v}{6.625*10^{-34}}[/tex]
[tex]\nu =2.70*10^{14} Hz[/tex]
ii)wavelength is given as
[tex]\lambda = \frac{c}{\nu}[/tex]
[tex]= \frac{3*10^8}{2.70*10^{14}} = 1.10*10^{-6} m[/tex]
