Respuesta :
Answer:
(a). The average speed of the car is 12.75 m/s
(b). The distance is 43.35 m.
Explanation:
Given that,
Initial speed = -25.5 m/s
Final speed = 0
Time = 3.4 s
(a). We need to calculate the average speed
Using formula of average speed
[tex]v_{avg}=\dfrac{v_{f}-v_{i}}{2}[/tex]
Put the value into the formula
[tex]v_{avg}=\dfrac{0-(-25.5)}{2}[/tex]
[tex]v_{avg}=12.75\ m/s[/tex]
(b). We need to calculate the acceleration
Using equation of motion
[tex]v_{f}=v_{i}+at[/tex]
[tex]a =\dfrac{v_{f}-v_{i}}{t}[/tex]
[tex]a=\dfrac{-25.5-0}{3.4}[/tex]
[tex]a=-7.5\ m/s^2[/tex]
We need to calculate the distance
Using equation of motion
[tex]s = ut+\dfrac{1}{2}at^2[/tex]
[tex]s=25.5\times3.4+\dfrac{1}{2}\times(-7.5)\times(3.4)^2[/tex]
[tex]s=43.35\ m[/tex]
Hence, (a). The average speed of the car is 12.75 m/s
(b). The distance is 43.35 m.
