Answer:
voltage across capacitor [tex]V_C=i\times X_C=0.022\times 0.04=9\times 10^{-4}V[/tex]
Voltage across resistor [tex]V_R=i\times R=0.022\times 2000=80V[/tex]
Explanation:
We have given resistance R = 2000 OHM
Capacitance [tex]C=1000\mu F=0.001F[/tex]
Voltage V = 45 volt
Frequency = 4000 Hz
Capacitive reactance [tex]X_C=\frac{1}{\omega C}=\frac{1}{2\times \pi \times 4000\times 0.001}=0.04ohm[/tex]
Impedance [tex]Z=\sqrt{R^2+X_C^2}=\sqrt{2000^2+0.04^2}=2000ohm[/tex]
Current [tex]i=\frac{V}{Z}=\frac{45}{2000}=0.022A[/tex]
Now voltage across capacitor [tex]V_C=i\times X_C=0.022\times 0.04=9\times 10^{-4}V[/tex]
Voltage across resistor [tex]V_R=i\times R=0.022\times 2000=80V[/tex]
