Answer:0.21
Explanation:
Given
Two point charges are brought closer together, increasing the force by a factor of 22
Let the original force be
[tex]F=\frac{kq_1q_2}{r^2}---1[/tex]
where [tex]q_1,q_2[/tex] are charges and r is the distance between them
new force [tex]F'=\frac{kq_1q_2}{r'^2}----2[/tex]
divide 1 & 2
[tex]\frac{F'}{F}=\frac{\frac{kq_1q_2}{r'^2}}{\frac{kq_1q_2}{r^2}}[/tex]
[tex]22=\frac{r^2}{r'^2}[/tex]
[tex]r'=\frac{r}{\sqrt{22}}\approx 0.213 r[/tex]
Distance between them is decrease by a factor of 0.21
