Answer:
a) [Tris0] : [Tris] = 1 : 100
b) Range = 7.1 to 9.1
Explanation:
a) Calculation of ratio of the basic and the acidic forms of tris
pH of a buffer is calculate using Henderson-Hasselbalch equation
[tex]pH = pKa+log\frac{Salt}{Acid}[/tex]
Conjugate acid of Tris dissociated as
[tex]Tris \leftrightharpoons Tris0 + H^+[/tex]
For tris,
Salt or Basic form = tris0
Acid or Acidic form = Tris
pKa = 8.1
pH = 6.1
[tex]pH = pKa+log\frac{Tris0}{Tris}[/tex]
[tex]6.1 = 8.1+log\frac{Tris0}{Tris}[/tex]
[tex]log\frac{Tris0}{Tris} = -2[/tex]
[tex]\frac{Tris0}{Tris} = antilog (-2)[/tex]
[tex]\frac{Tris0}{Tris} = 10^{-2}[/tex]
[Tris0] : [Tris] = 1 : 100
b) Range of Tris
Range of any buffer is:
From (pKa -1) to (pKa+1)
So, range of Tris is:
From (8.1 - 1) to (8.1 +1)
or from 7.1 to 9.1