Answer:
[tex]\frac{Wm^2C^{\circ}}{m^2-C^{\circ}}[/tex]
Step-by-step explanation:
We are given that A=[tex]\frac{W}{m^2-C^{\circ}}[/tex]
B=[tex]m^2[/tex]
C=[tex]C^{\circ}[/tex]
We are given that [tex]D=A\times B\times C[/tex]
We have to find the unit if D
Substitute the values then we get
[tex]D=\frac{W}{m^2-C^{\circ}}\times m^2\times C^{\circ}=\frac{Wm^2C^{\circ}}{m^2-C^{\circ}}[/tex]
[tex]D=\frac{Wm^2C^{\circ}}{m^2-C^{\circ}}[/tex]
Hence, units of D=[tex]\frac{Wm^2C^{\circ}}{m^2-C^{\circ}}[/tex]
