Answer:
The linear expansion coefficient of the material is [tex]4.952\times10^{-5}\ K^{-1}[/tex]
Explanation:
Given that,
Volume = 1.5 l
Temperature = 20°C
Increased temperature = 55°C
Volume = 7.8 mL
We need to calculate the linear expansion coefficient of the material
Using formula of linear expansion
[tex]\Delta V=V_{0}\beta \Delta T[/tex]
[tex]\Delta V=V_{0}(3\alpha \Delta T)[/tex]
[tex]\alpha =\dfrac{\Delta V}{3V_{0}\Delta T}[/tex]
Put the value into the formula
[tex]\alpha=\dfrac{7.8\times10^{-3}}{3\times1.5\times(55-20)}[/tex]
[tex]\alpha=0.00004952[/tex]
[tex]\alpha=4.952\times10^{-5}\ K^{-1}[/tex]
Hence, The linear expansion coefficient of the material is [tex]4.952\times10^{-5}\ K^{-1}[/tex]
