Answer:
Acceleration is -30000 mi/h²
Distance travelled in the 3 seconds of deceleration is 261.888 feet
Explanation:
t = Time taken for the car to slow down = 3 s =
u = Initial velocity = 75 mi/h
v = Final velocity = 50 mi/h
s = Displacement
a = Acceleration
Equation of motion
[tex]v=u+at\\\Rightarrow a=\frac{v-u}{t}\\\Rightarrow a=\frac{50-75}{\frac{3}{3600}}\\\Rightarrow a=-30000\ mi/h^2[/tex]
Acceleration is -30000 mi/h²
[tex]v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{50^2-75^2}{2\times -30000}\\\Rightarrow s=0.0496\ mi[/tex]
Converting to feet
1 mile = 5280 feet
0.0496 mile = 0.0496×5280 = 261.888 feet
Distance travelled in the 3 seconds of deceleration is 261.888 feet
