Answer:
Time period, [tex]T=3.05\times 10^{-5}\ s[/tex]
Explanation:
Given that,
The quartz crystal used in an electric watch vibrates with a frequency of 32,768 Hz, f = 32768 Hz
We need to find the period of the crystal's motion. The relationship between the frequency and the time period is given by :
[tex]T=\dfrac{1}{f}[/tex]
T is the time period of the crystal's motion.
Time period is given by :
[tex]T=\dfrac{1}{32768}[/tex]
[tex]T=3.05\times 10^{-5}\ s[/tex]
So, the time period of the crystal's motion is [tex]3.05\times 10^{-5}\ s[/tex]. Hence, this is the required solution.
The time period of the quartz crystal used in an electric watch which vibrates with a frequency of 32,768 Hz is 3.05×10⁻⁵ seconds.
The time required to complete the one vibration is called the time period of the vibration, and this is measured in the seconds.
The time period is inversely proportional to the frequency of vibration, and it can be given as,
[tex]T=\dfrac{1}{f}[/tex]
Here, (f) is the frequency.
The quartz crystal used in an electric watch vibrates with a frequency of 32,768 Hz. Put the value of frequency in the above formula as,
[tex]T=\dfrac{1}{32768}\\T=3.05\times10^{-5}\rm s[/tex]
Hence, the time period of the quartz crystal used in an electric watch which vibrates with a frequency of 32,768 Hz is 3.05×10⁻⁵ seconds.
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