Answer:
110,000 base 2
Step-by-step explanation:
column 1 [the first position in the number]:
1+1=0, (carry 1)
column 2:
0+1 +1 (carried)=0, (carry 1)
column 3:
1+0+1 (carried)=0, (carry 1)
column 4:
0+1+1 (carried)=0, (carry 1)
column 5:
1+1+1=1, (carry 1)
then you write the last 1 'cause there is n number to add with:
[tex]10,101_{2}+11,011_{2}=110,000_{2}[/tex]
In binary system the highest number to write is 1, if you add 1+1, it jumps to 0, and you have to carry 1 to the next position.
If you are not sure about the sum, you can convert the numbers in base 2, to base 10, so you can know if it is correct:
[tex]10,101_{2}=21_{10}\\11,011_{2}=27_{10}\\110,000_{2}=48_{10}[/tex]
So 21+27=48.
In decimal system when you add 9+1, it jumps to 0 and then you have to carry 1 to the next position, because the the highest number you can write is 9.
