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If the volame ofa gas coetainer at 32°C changes froem 1.55 L to 753 ml, what will the final temperature be? Assume the pressure doesn't change and the amount of gas in the coatainer doesn't change. Remember that there are 1,000 ml in 1 L. O a. 149°C Ob. 353 C Oc. 273C O d.-125 C Oe None of the above.

Respuesta :

Answer : The final temperature of gas will be, 149 K

Explanation :

Charles' Law : It is defined as the volume of gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

[tex]V\propto T[/tex]

or,

[tex]\frac{V_1}{V_2}=\frac{T_1}{T_2}[/tex]

where,

[tex]V_1[/tex] = initial volume of gas = 1.55 L

[tex]V_2[/tex] = final volume of gas = 753 ml  = 0.753 L

[tex]T_1[/tex] = initial temperature of gas = [tex]32^oC=273+32=305K[/tex]

[tex]T_2[/tex] = final temperature of gas = ?

Now put all the given values in the above formula, we get the final temperature of the gas.

[tex]\frac{1.55L}{0.753L}=\frac{305K}{T_2}[/tex]

[tex]T_2=149K[/tex]

Therefore, the final temperature of gas will be, 149 K

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