Answer:
The equation of line is [tex]y=2x+20[/tex]
Step-by-step explanation:
The general equation of line that passes through points [tex](x_{1},y_1),(x_2,y_2)[/tex] is given by
[tex](y-y_1)=\frac{y_2-y_1}{x_2-x_1}\cdot (x-x_1)[/tex]
In our case one of the given point is (-8,4)
Also since it is given that the x-intercept of the line is -10 hence by definition of x-intercept the line also passes through (-10,0)
Thus taking
[tex](x_{1},y_1)[/tex] as (-8,4) and [tex](x_{2},y_2)[/tex] as (-10,0) in the general equation of line we get
[tex](y-4)=\frac{0-4}{-10-(-8)}\cdot (x-(-8))\\\\(y-4)=\frac{-4}{-2}\cdot (x+8)\\\\(y-4)=2(x+8)\\\\y=2x+20[/tex]
