Respuesta :
Answer: The mass of hydrogen gas and nitrogen gas produced is 0.45 g and 3.15 g respectively.
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] .....(1)
Given mass of water = 4.05 g
Molar mass of water = 18 g/mol
Putting values in equation 1, we get:
[tex]\text{Moles of water}=\frac{4.05g}{18g/mol}=0.225mol[/tex]
For the given chemical reaction:
[tex]2H_2O\rightarrow 2H_2+O_2[/tex]
- For hydrogen:
By Stoichiometry of the reaction:
2 moles of water is producing 2 moles of hydrogen gas
So, 0.225 moles of water will produce = [tex]\frac{2}{2}\times 0.225=0.225mol[/tex] of hydrogen gas.
Now, calculating the mass of hydrogen gas by using equation 1, we get:
Moles of hydrogen gas = 0.225 mol
Molar mass of hydrogen gas = 2 g/mol
Putting values in equation 1, we get:
[tex]0.225mol=\frac{\text{Mass of hydrogen gas}}{2g/mol}\\\\\text{Mass of hydrogen gas}=0.45g[/tex]
- For nitrogen:
By Stoichiometry of the reaction:
2 moles of water is producing 1 mole of nitrogen gas
So, 0.225 moles of water will produce = [tex]\frac{1}{2}\times 0.225=0.1125mol[/tex] of nitrogen gas.
Now, calculating the mass of nitrogen gas by using equation 1, we get:
Moles of nitrogen gas = 0.1125 mol
Molar mass of nitrogen gas = 28 g/mol
Putting values in equation 1, we get:
[tex]0.1125mol=\frac{\text{Mass of nitrogen gas}}{28g/mol}\\\\\text{Mass of nitrogen gas}=3.15g[/tex]
Hence, the mass of hydrogen gas and nitrogen gas produced is 0.45 g and 3.15 g respectively.
