Explanation:
Given that,
Separation between the plates, d = 3.1 mm = 0.0031 m
Capacitance of the capacitor, C = 23 pF
We need to find the area of the plate. The capacitance of a parallel plate capacitor is given by :
[tex]C=\dfrac{A\epsilon_0}{d}[/tex]
[tex]A=\dfrac{Cd}{\epsilon_0}[/tex]
[tex]A=\dfrac{23\times 10^{-12}\times 0.0031}{8.85\times 10^{-12}}[/tex]
[tex]A=0.0080\ m^2[/tex]
or
[tex]A=80\ cm^2[/tex]
So, the area of the plate is 80 square centimetres. Hence, this is the required solution.
