Answer:
[tex]L = 2.746 cm[/tex]
Explanation:
As we know that thermal expansion coefficient of aluminium is given as
[tex]\alpha = 24 \times 10^{-6} per ^oC[/tex]
now we also know that after thermal expansion the final length is given as
[tex]L = L_o(1 + \alpha \Delta T)[/tex]
here we know that
[tex]L_o = 2.739 cm[/tex]
[tex]\alpha = 24 \times 10^{-6}[/tex]
[tex]\Delta T = 108 - 0= 108^oC[/tex]
now we will have
[tex]L = 2.739(1 + 24 \times 10^{-6} (108))[/tex]
[tex]L = 2.746 cm[/tex]
