Answer:
Part 1) Number of electrons in 1 liter of water equals[tex]N=3.346\times 10^{26}[/tex]
Part 2) Net charge of all the electrons equals [tex]Charge=53.61\times 10^{6}[/tex]
Explanation:
Since we know that the density of water is 1 kilogram per liter thus we infer that mass of 1 liter of water is 1 kilogram hence we need to find electron's in 1 kg of water.
Now since it is given that molar mass of water is 18.0 grams this means that 1 mole of water contains 18 grams of water.
Hence by ratio and proportion number of moles in 1 kg water equals
[tex]n=\frac{1000}{18}[/tex]
Now by definition of mole we know that 1 mole of any substance is Avagadro Number of particles.
Hence the no of molecules in 'n' moles of water equals
[tex]n'=\frac{1000}{18}\cdot N_a\\\\n'=\frac{1000}{18}\cdot 6.023\times 10^{23}\\[\tex][tex]\\n'=3.346\times 10^{25}[/tex]
Now since it is given that each molecule has 10 electron's thus the total number of electrons in n' molecules equals
[tex]N=10\times 3.346\times 10^{25}\\\\N=3.346\times 10^{26}[/tex]
Part 2)
We know that charge of 1 electron equals [tex]1.602\times 10^{-19}C[/tex] the the charge of electrons in 'N' quantity equals
[tex]Charge=1.6022\times 10^{-19}\times 3.346\times 10^{26}\\\\Charge=52.61\times 10^{6}Columbs[/tex]
