Answer:
"[tex]e^x[/tex] is irrational for every nonzero integer x"
Step-by-step explanation:
The original statement is
"[tex]e^x[/tex] is rational for some nonzero integer x."
The negation is technically:
"It is NOT true that [tex]e^x[/tex] is rational for some nonzero integer x."
So it's expressing that it's false that [tex]e^x[/tex] can be rational for some nonzero integer x.
This just means that [tex]e^x[/tex] is always irrational when x is a nonzero integer.
Which can be worded as
"[tex]e^x[/tex] is irrational for every nonzero integer x"
