Answer: Yes, [tex]HCl[/tex] is a strong acid.
acid = [tex]HCl[/tex] , conjugate base = [tex]Cl^-[/tex] , base = [tex]H_2O[/tex], conjugate acid = [tex]H_3O^+[/tex]
Explanation:
According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.
Yes [tex]HCl[/tex] is a strong acid as it completely dissociates in water to give [tex]H^+[/tex] ions.
[tex]HCl\rightarrow H^++Cl^-[/tex]
For the given chemical equation:
[tex]HCl+H_2O\rightarrow H_3O^-+Cl^-[/tex]
Here, [tex]HCl[/tex] is loosing a proton, thus it is considered as an acid and after losing a proton, it forms [tex]Cl^-[/tex] which is a conjugate base.
And, [tex]H_2O[/tex] is gaining a proton, thus it is considered as a base and after gaining a proton, it forms [tex]H_3O^+[/tex] which is a conjugate acid.
Thus acid = [tex]HCl[/tex]
conjugate base = [tex]Cl^-[/tex]
base = [tex]H_2O[/tex]
conjugate acid = [tex]H_3O^+[/tex].