Answer:
81.42 km/h
Explanation:
t = Time taken for the car to slow down
u = Initial velocity = 100 km/h
v = Final velocity
s = Displacement = 20 m = 0.02 km
a = Acceleration = -6.5 m/s² = -0.0065×60×60×60×60 = -84240 km/h²
Equation of motion
[tex]v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times -84240\times 0.02+100^2}\\\Rightarrow v=81.42\ km/h[/tex]
Speed of the truck at the end of this distance is 81.42 km/h
