Answer: The moles of water produced are 1.54 moles.
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
Given mass of ethane = 15.42 g
Molar mass of ethane = 30.07 g/mol
Putting values in above equation, we get:
[tex]\text{Moles of ethane}=\frac{15.42g}{30.07g/mol}=0.513mol[/tex]
The chemical equation for the combustion of ethane follows:
[tex]2C_2H_6+5O_2\rightarrow 4CO2+6H_2O[/tex]
By Stoichiometry of the reaction:
2 moles of ethane produces 6 moles of water
So, 0.513 moles of ethane will produce = [tex]\frac{6}{2}\times 0.513=1.54mol[/tex] of water
Hence, the moles of water produced are 1.54 moles.
