Explanation:
It is given that,
The acceleration of the toboggan, [tex]a=1.8\ m/s^2[/tex]
Initial speed of the toboggan, u = 0
We need to find the distance covered by the toboggan. Using the second equation of motion as :
[tex]s=ut+\dfrac{1}{2}at^2[/tex]
At t = 1 s
[tex]s=\dfrac{1}{2}\times 1.8\times 1^2[/tex]
[tex]s_1=0.9\ m[/tex]
At t = 2 s
[tex]s=\dfrac{1}{2}\times 1.8\times 2^2[/tex]
[tex]s_2=3.6\ m[/tex]
At t = 3 s
[tex]s=\dfrac{1}{2}\times 1.8\times 3^2[/tex]
[tex]s_3=8.1\ m[/tex]
Hence, this is the required solution.
