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A particle moves with a constant speed of 6 m/s along a circular path of a radius of 4 m. What is the magnitude of its acceleration. Do not include units in your answer, assumed unit are m/s2.

Respuesta :

Answer:

Acceleration in circular path will be 9

Explanation:

We have given speed of the particle in circular path = 6 m/sec

Radius of the circular path = 4 m

We have to find the centripetal acceleration [tex]a_c[/tex]

We know that centripetal acceleration is given by [tex]a_c=\frac{v^2}{r}=\frac{6^2}{4}=9[/tex]

As in question it is given that don't include the unit

So acceleration will be 9