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A person is standing on a level floor. His head,upper torso,
arms and hands together weigh 438N and have a centerof gravity that
is 1.17m above the floor. His upper legsweigh 144N and have a
center of gravity that is 0.835m above thefloor. Finally, his lower
legs and feet together weigh 87Nand have a center of gravity that
is 0.270m above the floor. Relative to the floor, find the location
of the center of gravityfor the entire body.

Respuesta :

Answer:

g = 0.98 m

Explanation:

given data:

upper portion weight 438 N and its center of gravity is 1.17 m

upper legs weight 144 N and its center of gravity is 0.835 m

lower leg weight 88 N and its center of gravity is 0.270 m

position of center of gravity of whole body can be determine by using following relation

[tex]g = \frac{\sum ({m_i g_i)}}{\sum m_i}[/tex]

where [tex]m_i[/tex] is mass of respective part and [tex]g_i[/tex] is center of gravity

[tex]g = \frac{\sum{ 438\times 1.17 + 144\times 0.835 + 88\times 0.270}}{438+144+88}[/tex]

g = 0.98 m

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